平面度和直線度誤差的快速評定——增量算法

岳武陵
吳勇

南通大學機械工程學院,江蘇南通226007

摘　要:在平面度（直線度）誤差評定的最小包容區域法中,提出一個新的、快速的實施方法——增量算法。該法以計算幾何中凸殼的理論為依據,結合平面度（直線度）誤差評定中數據的特點,從4個（3個）測點的子集開始,通過評定子集的平面度（直線度）以及增加距子集包容面最遠的點構成新的子集的方法,逐步逼近精確解。該算法單調遞增收斂到精確解,時間復雜度為O（n1）。幾個算例證實了方法和結論的正確性。[著者文摘]


A Fast Evaluation Method for Flatness and Straightness Tolerance by Means of Incremental AlgorithmYUE Wu-ling, WU Yong College of Mechanical Engineering, Nantong University, Nantong, Jiangsu 226007, ChinaAbstract:A fast and accurate method called incremental algorithm is proposed to implement the minimum zone tolerance for evaluating flatness or straightness errors. The algorithm is based on the convex - hull theory in computational geometry and also explores the properties of the measurement data. The algorithm starts from a subset with four （three） measurement points. If the bounding flats or straights determined by current subset can cover the whole remaining set, the distance between the bounding planes （lines） is the final accurate flatness （straightness）. Otherwise, put the point with maximum distance from the bounding planes into current subset, and repeat the previous step for the new subset. It is proved that the sequence of flatness （straightness） of these subsets monotonously increasingly converges to the accurate result. The timing complexity is only O （n1）. Several examples verify the correctness of this algorithm.[著者文摘]

Key words:Metrology ; Tolerance evaluation; Flatness ; Straightness ; Minimum zone ; Incremental algorithm

可否考多個項目檢鑒定員證？如沒有某個項目檢定員證，那可不可以從事這項目的檢定？

工廠一般采用對角線法，只有在有爭議的情況下才采用最小區域法。

可否考多個項目檢鑒定員證？如沒有某個項目檢定員證，那可不可以從事這項目的檢定？
sssssq 發表于 2009-2-16 22:17

當然可以考多個項目的，如果沒某個項目的檢定員證，應該是不可以簽字的