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標題: 四舍六入五成雙EXCEL實現 [打印本頁]

作者: wangyiyong7703 時間: 2023-2-22 16:59
標題: 四舍六入五成雙EXCEL實現
=IF(MID(A2,FIND(".",A2,1)+B2+1,1)*1<5,LEFT(A2,B2+FIND(".",A2,1)),IF(AND(MID(A2,FIND(".",A2,1)+B2+1,1)*1=5,RIGHT(A2,LEN(A2)-FIND(".",A2,1)-B2)*1=5*POWER(10,LEN(A2)-FIND(".",A2,1)-B2-1),INT(MID(A2,FIND(".",A2,1)+B2,1)*1/2)=MID(A2,FIND(".",A2,1)+B2,1)*1/2),LEFT(A2,B2+FIND(".",A2,1)),LEFT(A2,B2+FIND(".",A2,1))*1+POWER(10,-B2)))

解析：
A2存有待修約值，
B2存有修約小數點保留位數N，
邏輯：如果小數點后第N+1位數字小于5 則結果為不進位；
      如果小數點后第N+1位數字等于5 且第N數數字為偶數則結果為不進位
      否則結果全部進位。

返回進位結果LEFT(A2,B2+FIND(".",A2,1))*1+POWER(10,-B2)，
返回不進位結果LEFT(A2,B2+FIND(".",A2,1))
不進位條件：
   小數點N+1位數字MID(A2,FIND(".",A2,1)+B2+1,1)*1小于5；
   小數點N+1位數字MID(A2,FIND(".",A2,1)+B2+1,1)*1等于5，且后面全為0的
   條件RIGHT(A2,LEN(A2)-FIND(".",A2,1)-B2)*1=5*POWER(10,LEN(A2)-FIND(".",A2,1)-B2-1)；

進位條件：不進位便是進位。

附：
奇偶判定：INT(MID(A2,FIND(".",A2,1)+B2,1)*1/2)=MID(A2,FIND(".",A2,1)+B2,1)*1/2)，成立為偶數
進位后：加數值POWER(10,-B2)
小數點從左到右所在位置：FIND(".",A2,1)

四舍六入五成雙在excel的實現.xlsx

9.43 KB, 下載次數: 93, 下載積分: 金幣 -1

C3是運算結果

作者: wangyiyong7703 時間: 2023-2-22 22:04
還有有效數字，里面公式太復雜了，就不作解析了。

四舍六入五成雙在excel的實現.xlsx

13.6 KB, 下載次數: 35, 下載積分: 金幣 -1

作者: frank001 時間: 2023-2-23 13:38
謝謝你的分享！

作者: wangyiyong7703 時間: 2023-2-23 15:16

frank001 發表于 2023-2-23 13:38
謝謝你的分享！

k7，原創作品，多多提意見，后期好改進

作者: NMR 時間: 2023-2-23 21:59

謝謝你的分享！

作者: 馮貴林 時間: 2023-2-24 08:23
怎么把它運用到自己的證書模板的數據處理過程中呢

作者: 錫林郭勒 時間: 2023-2-24 08:43
這可以解決好多問題，

作者: lreplay 時間: 2023-2-24 11:37
看不懂，但是大受震撼……

作者: frank001 時間: 2023-2-24 13:09

wangyiyong7703 發表于 2023-2-23 15:16
k7，原創作品，多多提意見，后期好改進

公式還有一個能改進的點，小數點后面最后一位為0時，小數位保留就會出現異常

作者: 五路車 時間: 2023-2-24 14:59
先進的科學技術，提高生產力水平，不錯

作者: stacay 時間: 2023-2-24 17:56
本帖最后由 stacay 于 2023-2-24 18:04 編輯

如果數據大于0.1可以用下面的公式。小于0.1就不大適用了。

假如原始數據在A1，則在B1或C1或D1其他列中輸入以下
=IF(TRUNC(MOD(ABS(A1*POWER(10,2)),2),2)=0.5,ROUNDDOWN(A1,2),ROUND(A1,2))

如果數據不在A1處，如在B1處，則需要把公式里的A1改成B1即可，照此類推
上面公式給出的是保留2位小數，如果保留3位，就把2改成3，保留0位則改成0，保留十位-1，百位-2，照此類推
=IF(TRUNC(MOD(ABS(A1*POWER(10,2)),2),2)=0.5,ROUNDDOWN(A1,2),ROUND(A1,2))

作者: wangyiyong7703 時間: 2023-2-24 21:10

frank001 發表于 2023-2-24 13:09
公式還有一個能改進的點，小數點后面最后一位為0時，小數位保留就會出現異常 ...

有改進版，這個只是初稿

作者: wangyiyong7703 時間: 2023-2-24 21:10

馮貴林發表于 2023-2-24 08:23
怎么把它運用到自己的證書模板的數據處理過程中呢

好弄注意引用即可

作者: wangyiyong7703 時間: 2023-2-24 21:45

stacay 發表于 2023-2-24 17:56
如果數據大于0.1可以用下面的公式。小于0.1就不大適用了。

假如原始數據在A1，則在B1或C1或D1其他列中輸入 ...

連續0和連續9就失效，好多文獻的公司也是這樣的，連續9正在想辦法，連續0沒有問題

作者: wangyiyong7703 時間: 2023-2-25 15:13
漏洞補好，1以下不含1，=IF(IFERROR(FIND(REPT("9",B2),A2,1),1)=3,("1."&REPT("0",B2-1)),IF(IFERROR(FIND(REPT("9",B2),(LEFT(A2,FIND(".",A2,1))&RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1))),1),1)=3,IF((LEFT(A2,FIND(".",A2,1))&RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))*1<("0."&REPT("9",B2)&"5")*1,("0."&REPT("0",INT(ABS(LOG(A2))))&REPT("9",B2)),("0." & REPT("0",INT(ABS(LOG(A2)))-1)&"1"& REPT("0",B2-1))),IF(OR(LEFT(RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2),1)*1<5,AND(5&REPT("0",LEN(RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2))-1)=RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2),ISEVEN(RIGHT(LEFT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2+2),1)*1))),ROUNDDOWN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2),ROUNDUP(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2))/POWER(10,INT(ABS(LOG(A2)))) & REPT("0",B2+INT(ABS(LOG(A2)))-IF(ROUNDUP(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2)=1,1,INT(ABS(LOG(A2)))-2)-LEN(IF(OR(LEFT(RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2),1)*1<5,AND(5&REPT("0",LEN(RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2))-1)=RIGHT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),LEN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)))-B2-2),ISEVEN(RIGHT(LEFT(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2+2),1)*1))),ROUNDDOWN(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2),ROUNDUP(LEFT(A2,FIND(".",A2,1)) & RIGHT(A2,LEN(A2)-INT(ABS(LOG(A2)))-FIND(".",A2,1)),B2))))))

作者: wangyiyong7703 時間: 2023-2-25 15:17

frank001 發表于 2023-2-24 13:09
公式還有一個能改進的點，小數點后面最后一位為0時，小數位保留就會出現異常 ...

請您親測一下，多提提意見，原創不易

作者: wangyiyong7703 時間: 2023-2-25 15:17

stacay 發表于 2023-2-24 17:56
如果數據大于0.1可以用下面的公式。小于0.1就不大適用了。

假如原始數據在A1，則在B1或C1或D1其他列中輸入 ...

請您親測一下，多提提意見，原創不易

作者: wangyiyong7703 時間: 2023-2-25 16:04
大于1的公式，目前10的N次方沒有弄，=IF(AND(IFERROR(FIND(REPT("9",C2),(A2/POWER(10,INT(LOG(A2))+1)),1),1)=3,(A2/POWER(10,INT(LOG(A2))+1))*1<("0."&REPT("9",C2)&"5")*1),("0."&REPT("9",C2)),IF(AND(IFERROR(FIND(REPT("9",C2),(A2/POWER(10,INT(LOG(A2))+1))*1,1),1)=3,OR((A2/POWER(10,INT(LOG(A2))+1))*1>("0."&REPT("9",C2)&"5")*1,(A2/POWER(10,INT(LOG(A2))+1))*1=("0."&REPT("9",C2)&"5")*1)),("1."&REPT("0",C2-1)),IF(IFERROR(FIND(REPT("9",C2),(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1))&RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1))),1),1)=3,IF((LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1))&RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))*1<("0."&REPT("9",C2)&"5")*1,("0."&REPT("0",INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1))))))&REPT("9",C2)),("0." & REPT("0",INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-1)&"1"& REPT("0",C2-1))),IF(OR(LEFT(RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2),1)*1<5,AND(5&REPT("0",LEN(RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2))-1)=RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2),ISEVEN(RIGHT(LEFT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2+2),1)*1))),ROUNDDOWN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2),ROUNDUP(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2))/POWER(10,INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))) & REPT("0",C2+INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-IF(ROUNDUP(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2)=1,1,INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-2)-LEN(IF(OR(LEFT(RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2),1)*1<5,AND(5&REPT("0",LEN(RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2))-1)=RIGHT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),LEN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)))-C2-2),ISEVEN(RIGHT(LEFT(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2+2),1)*1))),ROUNDDOWN(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2),ROUNDUP(LEFT((A2/POWER(10,INT(LOG(A2))+1)),FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)) & RIGHT((A2/POWER(10,INT(LOG(A2))+1)),LEN((A2/POWER(10,INT(LOG(A2))+1)))-INT(ABS(LOG((A2/POWER(10,INT(LOG(A2))+1)))))-FIND(".",(A2/POWER(10,INT(LOG(A2))+1)),1)),C2)))))))*POWER(10,INT(LOG(A2))+1)

作者: myoliveryong 時間: 2023-2-25 20:04

wangyiyong7703 發表于 2023-2-25 16:04
大于1的公式，目前10的N次方沒有弄，=IF(AND(IFERROR(FIND(REPT("9",C2),(A2/POWER(10,INT(LOG(A2))+1)),1) ...

你為啥要來計量，不去IT？還是從IT過來的？

作者: Ming1212 時間: 2023-2-26 10:10
謝謝你的分享！

作者: wangyiyong7703 時間: 2023-2-26 12:47
有效數位，補全A2輸待修約值，B2輸入有效數位，C2輸入公式IF(IFERROR(FIND(".",A2,1),0)=0,"",RIGHT(A2,LEN(A2)-IFERROR(FIND(".",A2,1),0)))；D2輸入公式：IF(INT(LOG(A2))<-1,(IF(TRUNC(A2)=0,"",TRUNC(A2))&C2)*1,IF(TRUNC(A2)=0,"",TRUNC(A2))&C2)；結果顯示公式：IF(LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)))=1,(LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)),LEFT((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)),1)&"."&IF((LEN(LEFT(D2,B2))-LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1))))=0,RIGHT((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)),LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)))-1),LEFT(RIGHT((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)),LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)))-1),LEN(RIGHT((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)),LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1)))-1))-1))&IF(INT(LOG(A2))-(LEN(LEFT(D2,B2))-LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1))))=0,""," E "&INT(LOG(A2))-(LEN(LEFT(D2,B2))-LEN((LEFT(D2,B2)+IF(OR(LEFT(RIGHT(D2,LEN(D2)-B2),1)*1<5,AND(ISEVEN(MID(D2,B2,1)),("5"&REPT("0",LEN(RIGHT(D2,LEN(D2)-B2))-1))-RIGHT(D2,LEN(D2)-B2)=0)),0,1))))))

作者: dxquan 時間: 2023-2-26 13:50
一個字“牛”

作者: xuhuilai 時間: 2023-2-27 08:48
牛啊，大佬。

作者: nn141008 時間: 2023-2-27 11:09
大寫的牛！！

作者: wangyiyong7703 時間: 2023-2-27 14:13
有效數字大于1，求公式可在附件中下載。已更新。如有好的意見和建議，請發貼。

四舍六入五成雙在excel（不再更新）.xlsx

27.31 KB, 下載次數: 13, 下載積分: 金幣 -1

作者: alin72 時間: 2023-2-27 14:23
太牛了。公式我看著都頭暈

作者: stacay 時間: 2023-2-27 15:30

wangyiyong7703 發表于 2023-2-25 15:17
請您親測一下，多提提意見，原創不易

EXCEL受限于浮點運算機制，是比較難處理的。

作者: yshf530 時間: 2023-2-27 15:58
謝謝你的分享，用心了

作者: wangyiyong7703 時間: 2023-2-27 17:05

stacay 發表于 2023-2-27 15:30
EXCEL受限于浮點運算機制，是比較難處理的。

確實碰到這種情況，改變了思路，才破解了。很不容易。不用宏程序解決確實太難了。我用宏程序測試過，目前還沒有發現異常，宏程序在文件里面。可運行

四舍六入五成雙在excel（不再更新）.xlsx

27.31 KB, 下載次數: 28, 下載積分: 金幣 -1

下載這個看一哈

作者: 22063974 時間: 2023-3-1 09:52
非常好用的，謝謝，這是編程界的來到了計量領域

作者: Maybeanyou 時間: 2023-3-1 13:56
謝謝，幫大忙了

作者: 26826768 時間: 2023-3-1 14:40
牛啊！這個數據處理太牛了

作者: 于是乎 時間: 2023-3-1 15:43
謝謝你的分享，真是太牛了。

作者: azthankyou 時間: 2023-3-9 19:02
厲害了！我的哥！

作者: wangyiyong7703 時間: 2023-9-16 00:46
A2 輸入待修約數，B2輸入小數點，C2輸入公式

IF(LEN(IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))=LEN(INT(A2)),IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2))&"."&REPT("0",B2),IF(LEN(INT(A2*POWER(10,B2)))+1>LEN((IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))),(IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))&REPT("0",LEN(INT(A2*POWER(10,B2)))-1-LEN((IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2))))),IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2))))

作者: wangyiyong7703 時間: 2023-9-16 01:01
A2輸入待修約數字，B2輸入保留小數點位數，C2輸入公式

IF(B2=0,IF(OR(AND(ISEVEN(INT(A2)),A2-INT(A2)=0.5),A2-INT(A2)<0.5),INT(A2),INT(A2)+1),IF(LEN(IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))=LEN(INT(A2)),IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2))&"."&REPT("0",B2),IF(LEN(INT(A2*POWER(10,B2)))+1>LEN((IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))),(IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))&REPT("0",LEN(INT(A2*POWER(10,B2)))-1-LEN((IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2))))),IF(OR(AND(ISEVEN(INT(A2*POWER(10,B2))),A2*POWER(10,B2)-INT(A2*POWER(10,B2))=0.5),A2*POWER(10,B2)-INT(A2*POWER(10,B2))<0.5),INT(A2*POWER(10,B2))/POWER(10,B2),(INT(A2*POWER(10,B2))+1)/POWER(10,B2)))))

作者: 唐家琨少 時間: 2023-12-15 16:48
大佬思路太牛了，看了一下都是用很基礎的excel公式解決的，這個應該就不存在文件轉發給別人之后會因為office不一樣或者對方用WPS打開而失效了。

作者: wangyiyong7703 時間: 2023-12-19 15:50

唐家琨少發表于 2023-12-15 16:48
大佬思路太牛了，看了一下都是用很基礎的excel公式解決的，這個應該就不存在文件轉發給別人之后會因為offic ...

關注之我后，還有更新的你可以看一哈其他的。用VB做過。現在做的這個還是有漏洞

作者: allene 時間: 2023-12-25 08:21
謝謝你的分享

作者: zzylyau126 時間: 2023-12-25 11:06
這個厲害！條件太多，復雜

作者: redxsnake 時間: 2023-12-28 16:17
講的很好，受益匪淺！學習了

作者: yuanxu2021 時間: 2024-11-16 11:07
感謝樓主分享！

作者: ge1422915514 時間: 2024-11-16 11:35

高級，提高生產力水平，不錯

作者: a7835209 時間: 2024-11-29 10:14
感謝樓主分享！下載學習了

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